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If cosA + cosB + cosC = 3, then what is the value of sinA + sinB + sinC?
Answer & Solution
Correct Answer:
Option
C
cosA + cosB + cosC = 3
⇒ putting A, B, C = 0
1 + 1 + 1 = 3
3 = 3 Satisfied
So, sinA + sinB + sinC
= sin0° + sin0° + sin0°
= 0 + 0 + 0
= 0
⇒ putting A, B, C = 0
1 + 1 + 1 = 3
3 = 3 Satisfied
So, sinA + sinB + sinC
= sin0° + sin0° + sin0°
= 0 + 0 + 0
= 0
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