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If cos(A - α) = p, sin(A - β) = q, then the value of cos2(α - β) + 2pqsin(α - β) is:
Answer & Solution
Correct Answer:
Option
C
cos(A - α) = p, sin(A - β) = q
Here, two equation, and four variable,
So, α = β = 0,
cosA = p, sinA = q
Now, cos2(α - β) + 2pq sin(α - β)
cos20 + 2pq × sin0
1 + 0 = 1
By option, (C) = p2 + q2
= cos2A + sin2A
= 1
Here, two equation, and four variable,
So, α = β = 0,
cosA = p, sinA = q
Now, cos2(α - β) + 2pq sin(α - β)
cos20 + 2pq × sin0
1 + 0 = 1
By option, (C) = p2 + q2
= cos2A + sin2A
= 1
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