If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond length is given by
A. $$\frac{{{{\text{f}}_{\text{t}}}{\text{d}}}}{{4{{\text{f}}_{\text{b}}}}}$$
B. $$\frac{\pi }{4} \times \frac{{{{\text{f}}_{\text{t}}}{\text{d}}}}{{{{\text{f}}_{\text{b}}}}}$$
C. $$\frac{{\pi {{\text{f}}_{\text{t}}}{{\text{d}}^2}}}{{{{\text{f}}_{\text{b}}}}}$$
D. $$\frac{\pi }{4} \times \frac{{{{\text{f}}_{\text{t}}}{{\text{d}}^3}}}{{{{\text{f}}_{\text{b}}}}}$$
Answer: Option A

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