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If each edge of a cube is increased by 10% then the percentage increase in its surface area is:
Answer & Solution
Correct Answer:
Option
A
$${l_1} \to {l_2}$$
\[10\xrightarrow[{ + 10 \uparrow }]{}{l_2}\]
$$\eqalign{ & {S_1} \to {S_2} \cr & 6 \times {10^2} \to 6 \times {11^2} \cr & 100 \to 121 \cr & = \frac{{21}}{{100}} \times 100 \cr & = 21\% \cr} $$
\[10\xrightarrow[{ + 10 \uparrow }]{}{l_2}\]
$$\eqalign{ & {S_1} \to {S_2} \cr & 6 \times {10^2} \to 6 \times {11^2} \cr & 100 \to 121 \cr & = \frac{{21}}{{100}} \times 100 \cr & = 21\% \cr} $$
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