If each edge of a cube is increased by 10% then the percentage increase in its surface area is:
A. 21%
B. 19%
C. 22%
D. 20%
Answer: Option A
Solution(By Examveda Team)
$${l_1} \to {l_2}$$\[10\xrightarrow[{ + 10 \uparrow }]{}{l_2}\]
$$\eqalign{ & {S_1} \to {S_2} \cr & 6 \times {10^2} \to 6 \times {11^2} \cr & 100 \to 121 \cr & = \frac{{21}}{{100}} \times 100 \cr & = 21\% \cr} $$
Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
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