If $$F\left( s \right) = L\left[ {f\left( t \right)} \right] = {{2\left( {s + 1} \right)} \over {{s^2} + 4s + 7}}$$ then the initial and final values of f(t) are respectively
A. 0, 2
B. 2, 0
C. $$0,{2 \over 7}$$
D. $${2 \over 7},0$$
Answer: Option B
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