If for non-zero x, \[{\rm{af}}\left( {\rm{x}} \right) + {\rm{bf}}\left( {\frac{1}{{\rm{x}}}} \right) = \frac{1}{{\rm{x}}} - 25\] where a ≠ b then \[\int\limits_1^2 {{\rm{f}}\left( {\rm{x}} \right){\rm{dx}}} \] is
A. \[\frac{1}{{{{\rm{a}}^2} - {{\rm{b}}^2}}}\left[ {a\left( {\ln 2 - 25} \right) + \frac{{47{\rm{b}}}}{2}} \right]\]
B. \[\frac{1}{{{{\rm{a}}^2} - {{\rm{b}}^2}}}\left[ {a\left( {2\ln 2 - 25} \right) - \frac{{47{\rm{b}}}}{2}} \right]\]
C. \[\frac{1}{{{{\rm{a}}^2} - {{\rm{b}}^2}}}\left[ {a\left( {2\ln 2 - 25} \right) + \frac{{47{\rm{b}}}}{2}} \right]\]
D. \[\frac{1}{{{{\rm{a}}^2} - {{\rm{b}}^2}}}\left[ {a\left( {\ln 2 - 25} \right) - \frac{{47{\rm{b}}}}{2}} \right]\]
Answer: Option A

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