If four coins are tossed, the probability of getting two heads and two tails is -
A. $$\frac{{3}}{{8}}$$
B. $$\frac{{6}}{{11}}$$
C. $$\frac{{2}}{{5}}$$
D. $$\frac{{4}}{{5}}$$
Answer: Option A
Solution (By Examveda Team)
Since four coins are tossed, sample space = 24Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = $$\frac{6}{{{2^4}}}$$ = $$\frac{3}{8}$$
This Question Belongs to Arithmetic Ability >> Probability
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