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If in a three digits number the last two digits places are interchanged a new number is formed which is greater than the original number by 45. What is the difference between the last two digits of that number ?
Answer & Solution
Correct Answer:
Option
D
Three digit number = 100x + 10y + z
To make number after changing last two digit = 100x + 10z + y
Now,
100x + 10y + z = 100x + 10z + y - 45
9z - 9y = 45
z - y = 5
To make number after changing last two digit = 100x + 10z + y
Now,
100x + 10y + z = 100x + 10z + y - 45
9z - 9y = 45
z - y = 5
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