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If $$\log \frac{a}{b} + \log \frac{b}{a} = $$ $$\,\log \left( {a + b} \right),$$ then -
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \log \frac{a}{b} + \log \frac{b}{a} = \log \left( {a + b} \right) \cr
& \Rightarrow \log \left( {a + b} \right) = \log \left( {\frac{a}{b} \times \frac{b}{a}} \right) \cr
& \Rightarrow \log \left( {a + b} \right) = \log 1 \cr
& So,\,\,\,a + b = 1 \cr} $$
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