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$${\rm{If}}\log {a \over b} + \log {b \over a} = \log \left( {a + b} \right),{\rm{then:}}$$

A. a + b = 1

B. a - b = 1

C. a = b

D. a2 - b2 = 1

Answer: Option A

Solution(By Examveda Team)

$$\eqalign{ & \log {a \over b} + \log {b \over a} = \log \left( {a + b} \right) \cr & \Rightarrow \log \left( {a + b} \right) = \log \left( {{a \over b} \times {b \over a}} \right) = \log 1 \cr & So,a + b = 1 \cr} $$

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