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If n is an integer, how many values of n will give an integral value of $$\left( {\frac{{16{n^2} + 7n + 6}}{n}} \right)$$ ?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& = \left( {\frac{{16{n^2} + 7n + 6}}{n}} \right) \cr
& = \left( {\frac{{16{n^2}}}{n} + \frac{{7n}}{n} + \frac{6}{n}} \right) \cr
& = \left( {16n + 7 + \frac{6}{n}} \right) \cr} $$
For $$\left( {16n + 7 + \frac{6}{n}} \right)$$ to be an integer, we may have n = 1 or n = 2 or n = 3 or n = 6
Hence, 4 value of n will give the desired result.
For $$\left( {16n + 7 + \frac{6}{n}} \right)$$ to be an integer, we may have n = 1 or n = 2 or n = 3 or n = 6
Hence, 4 value of n will give the desired result.
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