If n is an integer, then (n3 - n) is always divisible by :
A. 4
B. 5
C. 6
D. 7
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \left( {{n^3} - n} \right){\text{ and n is any integer}} \cr & {\text{put n = 2 so, }}{{\text{2}}^3} - 2 = 6 \cr & {\text{It will be always divisible by 6}} \cr & {\text{(put n = 2, 3, 4}}....{\text{)}} \cr & {\text{(n = 2, 3, 4}}.....{\text{)}} \cr} $$Join The Discussion
Comments ( 2 )
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
Why you put n=2
This type having a another option a.3 b.6 c 12 d.18 then solution is?