If $$\root 3 \of {\text{N}} $$ lies between 6 and 7, where N is an integer then how many values N can take?
A. 125
B. 126
C. 127
D. 128
Answer: Option B
Solution (By Examveda Team)
6 < $$\root 3 \of {\text{N}} $$ < 7On cubing,
216 < N < 343
Number of terms = (342 - 217) + 1 = 125 + 1 = 126
This Question Belongs to Arithmetic Ability >> Number System
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