If $${\text{se}}{{\text{c}}^2}\theta + {\text{ta}}{{\text{n}}^2}\theta = \frac{7}{{12}}{\text{,}}$$ then $${\text{se}}{{\text{c}}^4}\theta $$ - $${\text{ta}}{{\text{n}}^4}\theta $$ = ?
A. $$\frac{7}{{12}}$$
B. $$\frac{1}{2}$$
C. $$\frac{7}{2}$$
D. 1
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & \left( {{\text{se}}{{\text{c}}^4}\theta - {\text{ta}}{{\text{n}}^4}\theta } \right) \cr & \Rightarrow \left( {{\text{se}}{{\text{c}}^2}\theta - {\text{ta}}{{\text{n}}^2}\theta } \right)\left( {{\text{se}}{{\text{c}}^2}\theta + {\text{ta}}{{\text{n}}^2}\theta } \right) \cr & \Rightarrow 1 \times \left( {{\text{se}}{{\text{c}}^2}\theta + {\text{ta}}{{\text{n}}^2}\theta } \right)[1 + {\text{ta}}{{\text{n}}^2}\theta = {\text{se}}{{\text{c}}^2}\theta ] \cr & \Rightarrow 1 \times \frac{7}{{12}} \cr & \Rightarrow \frac{7}{{12}} \cr} $$This Question Belongs to Arithmetic Ability >> Trigonometry
Join The Discussion
Comments ( 2 )
Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
An error has been resolved. Thanks, Amal for reporting an issue
There is a mistake in question