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If $$\sec \theta - \tan \theta = \frac{1}{{\sqrt 3 }}{\text{,}}$$    the value of $$\sec \theta $$ . $$\tan \theta $$  = ?

A. $$\frac{4}{{\sqrt 3 }}$$

B. $$\frac{2}{{\sqrt 3 }}$$

C. $$\frac{2}{3}$$

D. $$\frac{1}{{\sqrt 3 }}$$

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & {\bf{Shortcut\,\, method:}} \cr & {\text{Put }}\theta = {30^ \circ } \cr & \Rightarrow \sec \theta - \tan \theta = \frac{1}{{\sqrt 3 }} \cr & \Rightarrow \sec {30^ \circ } - \tan {30^ \circ } = \frac{1}{{\sqrt 3 }} \cr & \Rightarrow \frac{2}{{\sqrt 3 }} - \frac{1}{{\sqrt 3 }} = \frac{1}{{\sqrt 3 }} \cr & \Rightarrow \frac{1}{{\sqrt 3 }} = \frac{1}{{\sqrt 3 }}{\text{ }}\left( {{\text{Satisfied}}} \right) \cr & \sec \theta = {30^ \circ } \cr & \Rightarrow \sec \theta .\tan \theta \cr & \Rightarrow \sec {30^ \circ }.\tan {30^ \circ } \cr & \Rightarrow \frac{2}{{\sqrt 3 }} \times \frac{1}{{\sqrt 3 }} \cr & \Rightarrow \frac{2}{3} \cr} $$

This Question Belongs to Arithmetic Ability >> Trigonometry

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