If sec15θ = cosec15θ (0° < θ < 10°) then the value of θ is?
A. 9°
B. 5°
C. 8°
D. 3°
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & \sec 15\theta = \operatorname{cosec} 15\theta \cr & \Rightarrow \frac{1}{{\cos {{15} }\theta }} = \frac{1}{{\sin 15\theta }} \cr & \Rightarrow \frac{{\sin 15\theta }}{{{\text{cos15}}\theta }} = 1 \cr & \Rightarrow {\text{tan15}}\theta = 1 \cr & \Rightarrow {\text{tan15}}\theta = {\text{tan}}{45^ \circ } \cr & \Rightarrow 15\theta = {45^ \circ } \cr & \Rightarrow \theta = \frac{{45}}{{15}} \cr & \Rightarrow \theta = {3^ \circ } \cr} $$Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
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