If secα + tanα = 2, then the value of sinα is (assume that 0 < α < 90°)
A. 0.4
B. 0.5
C. 0.6
D. 0.8
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & sec\alpha + \tan \alpha = 2\,.....(i) \cr & sec\alpha - \tan \alpha = \frac{1}{2}\,.....(ii) \cr & {\text{Adding equation (i) and (ii)}} \cr & {\text{2sec}}\alpha = 2 + \frac{1}{2} \cr & \sec \alpha = \frac{{5 \to {\text{H}}}}{{4 \to {\text{B}}}} \cr} $$$$\sin \alpha = \frac{3}{5} = 0.6$$
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