If sinθ = $$\frac{9}{{41}},$$ 0° < θ < 90° then what is the value of cotθ?
A. $$\frac{{39}}{9}$$
B. $$\frac{{35}}{8}$$
C. $$\frac{{40}}{9}$$
D. $$\frac{{47}}{8}$$
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & \sin \theta = \frac{9}{{41}} \cr & \frac{P}{H} = \frac{9}{{41}},\,\,B = 40 \cr & \Rightarrow \cot \theta = \frac{B}{P} = \frac{{40}}{9} \cr} $$This Question Belongs to Arithmetic Ability >> Trigonometry
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