If $$\sqrt 2 $$ : $$\left( {1 + \sqrt 3 } \right)$$ :: $$\sqrt 6 $$ : $$x$$, then $$x$$ is equal to -
A. $$\sqrt 3 + 3$$
B. $$1 - \sqrt 3 $$
C. $$1 + \sqrt 3 $$
D. $$\sqrt 3 - 3$$
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & = \sqrt 2 :\left( {1 + \sqrt 3 } \right)::\sqrt 6 :x \cr & \Rightarrow \sqrt {2}x = \sqrt 6 \left( {1 + \sqrt 3 } \right) \cr & \Rightarrow x = \frac{{\sqrt 6 \left( {1 + \sqrt 3 } \right)}}{{\sqrt 2 }} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = \sqrt 3 \left( {1 + \sqrt 3 } \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = \sqrt 3 + 3 \cr} $$Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
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