If $$\sqrt {{\text{4096}}} $$ = 64, then the value of $$\sqrt {{\text{40}}{\text{.96}}} $$ $$ + $$ $$\sqrt {{\text{0}}{\text{.4096}}} $$ $$ + $$ $$\sqrt {{\text{0}}{\text{.004096}}} $$ $$ + $$ $$\sqrt {{\text{0}}{\text{.00004096}}} $$ up to two place of decimals is = ?
A. 7.09
B. 7.10
C. 7.11
D. 7.12
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{According to question,}} \cr & \sqrt {40.96} {\text{ + }}\sqrt {0.4096} {\text{ + }}\sqrt {0.004096} {\text{ + }}\sqrt {0.00004096} \cr & \Rightarrow \sqrt {\frac{{4096}}{{100}}} + \sqrt {\frac{{4096}}{{10000}}} + \sqrt {\frac{{4096}}{{1000000}}} + \sqrt {\frac{{4096}}{{100000000}}} \cr & \Rightarrow \frac{{64}}{{10}} + \frac{{64}}{{100}} + \frac{{64}}{{1000}} + \frac{{64}}{{10000}} \cr & \Rightarrow 6.4 + 0.64 + 0.064 + 0.0064 \cr & \Rightarrow 7.11 \cr} $$Related Questions on Simplification
A. 20
B. 80
C. 100
D. 200
E. None of these
A. Rs. 3500
B. Rs. 3750
C. Rs. 3840
D. Rs. 3900
E. None of these
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