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If tanθ + cotθ = -2, then the value of tan9θ + cot9θ is:
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \tan \theta + \cot \theta = - 2 \cr
& \Rightarrow \tan \theta + \frac{1}{{\tan \theta }} = - 2 \cr
& \Rightarrow \tan \theta = - 1 \cr
& \Rightarrow {\tan ^9}\theta + {\cot ^9}\theta \cr
& = {\tan ^9}\theta + \frac{1}{{{{\tan }^9}\theta }} \cr
& = {\left( { - 1} \right)^9} + \frac{1}{{{{\left( { - 1} \right)}^9}}} \cr
& = - 1 - 1 \cr
& = - 2 \cr} $$
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