If tensile stress of a steel rod of diameter ‘D’ is 1400 kg/cm2 and bond stress is 6 kg/cm2, the required bond length of the rod is
A. 30 D
B. 39 D
C. 50 D
D. 59 D
Answer: Option D
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Bond length or development length = d*tensilestress/4*bond stress.
D*1400/4*6 = 58.33.
(Dia/4×tbd)
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