If the code shown below is executed on a little endian machine, then what will be the output of the following C code?
#include<stdio.h>
main()
{
int y=1;
printf("%d", (*(char*)&y));
}
#include<stdio.h>
main()
{
int y=1;
printf("%d", (*(char*)&y));
}A. 1
B. 1000
C. 9999
D. 0
Answer: Option A
This Question Belongs to C Program >> C Miscellaneous
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