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If the expected time for completion of a project is 10 days with a standard deviation of 2 days, the expected time of completion of the project with 99.9% probability is

A. 4 days

B. 6 days

C. 10 days

D. 16 days

Answer: Option D


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Comments ( 7 )

  1. Karma Dorjay
    Karma Dorjay :
    6 months ago

    For 99.9% value of probability value from chart is 3.
    So
    Here Te= 10 days
    Z= Ts-To/deviation
    3= Ts-10/2 , solving this we get Ts= 16 ... So correct answer is D :)

  2. Anagha Bhagat
    Anagha Bhagat :
    4 years ago

    Z=(Ts-Te)/σt
    3=(Ts-10)/2
    =16 option D

  3. Sanjeet Malhotra
    Sanjeet Malhotra :
    4 years ago

    -3sigma to 3sigma =99.7 to 99.9%
    3sigma =3×2=6
    Expected time =10 +6=16

  4. Sanjeet Malhotra
    Sanjeet Malhotra :
    4 years ago

    -3sigma to 3sigma =99.7 to 99.9%
    3sigma =3×2=6
    Expected time =10 +6=16

  5. Shruti Jadhav
    Shruti Jadhav :
    4 years ago

    P%=99.9%
    6= 2days
    Te=10days
    Tou=?
    From table of tou and percentage for 99.9% the Tou value is 3.
    Tou= Ts-Te / 2 so, TS=16 days

  6. Shruti Jadhav
    Shruti Jadhav :
    4 years ago

    P%=99.9%
    6= 2days
    Te=10days
    Tou=?
    From table of tou and percentage for 99.9% the Tou value is 3.
    Tou= Ts-Te / 2 so, TS=16 days

  7. Shreeharsha Kp
    Shreeharsha Kp :
    5 years ago

    Pls explains

Related Questions on Construction Planning and Management

If to, tp and tm are the optimistic, pessimistic and most likely time estimates of an activity respectively, the expected time t of the activity will be

A. $$\frac{{{{\text{t}}_{\text{o}}} + 3{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{2}$$

B. $$\frac{{{{\text{t}}_{\text{o}}} + 3{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{3}$$

C. $$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{4}$$

D. $$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{5}$$

E. $$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{6}$$