If the expected time for completion of a project is 10 days with a standard deviation of 2 days, the expected time of completion of the project with 99.9% probability is
A. 4 days
B. 6 days
C. 10 days
D. 16 days
Answer: Option D
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Comments ( 7 )
The normal time required for the completion of project in the above problem is
A. 9 days
B. 13 days
C. 14 days
D. 19 days
A. $$\frac{{{{\text{t}}_{\text{o}}} + 3{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{2}$$
B. $$\frac{{{{\text{t}}_{\text{o}}} + 3{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{3}$$
C. $$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{4}$$
D. $$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{5}$$
E. $$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{6}$$
A construction schedule is prepared after collecting
A. Number of operations
B. Output of labour
C. Output of machinery
D. All the above
A. 3.5 and $$\frac{5}{6}$$
B. 5 and $$\frac{{25}}{{36}}$$
C. 3.5 and $$\frac{{25}}{{36}}$$
D. 4 and $$\frac{5}{6}$$
For 99.9% value of probability value from chart is 3.
So
Here Te= 10 days
Z= Ts-To/deviation
3= Ts-10/2 , solving this we get Ts= 16 ... So correct answer is D :)
Z=(Ts-Te)/σt
3=(Ts-10)/2
=16 option D
-3sigma to 3sigma =99.7 to 99.9%
3sigma =3×2=6
Expected time =10 +6=16
-3sigma to 3sigma =99.7 to 99.9%
3sigma =3×2=6
Expected time =10 +6=16
P%=99.9%
6= 2days
Te=10days
Tou=?
From table of tou and percentage for 99.9% the Tou value is 3.
Tou= Ts-Te / 2 so, TS=16 days
P%=99.9%
6= 2days
Te=10days
Tou=?
From table of tou and percentage for 99.9% the Tou value is 3.
Tou= Ts-Te / 2 so, TS=16 days
Pls explains