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Here Te= 10 days
Z= Ts-To/deviation
3= Ts-10/2 , solving this we get Ts= 16 ... So correct answer is D :)
3=(Ts-10)/2
=16 option D
3sigma =3×2=6
Expected time =10 +6=16
3sigma =3×2=6
Expected time =10 +6=16
6= 2days
Te=10days
Tou=?
From table of tou and percentage for 99.9% the Tou value is 3.
Tou= Ts-Te / 2 so, TS=16 days
6= 2days
Te=10days
Tou=?
From table of tou and percentage for 99.9% the Tou value is 3.
Tou= Ts-Te / 2 so, TS=16 days