If the rms current through a 4.7 kΩ resistor is 4 mA, the peak voltage drop across the resistor is
A. 4 V
B. 18.8 V
C. 26.6 V
D. 2.66 V
Answer: Option C
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Related Questions on Alternating Current and Voltage
To produce an 800 Hz sine wave, a four-pole generator must be operated at
A. 200 rps
B. 400 rps
C. 800 rps
D. 1,600 rps
A. Wave A leads wave B by 15°
B. Wave A lags wave B by 15°
C. Wave A leads wave B by 105°
D. Wave A lags wave B by 105°
V{RMS} = I{RMS} × R
V_{RMS} = 0.004× 4700= 18.8V
V_{peak} = V_{RMS} × √2
V_{peak = 18.8×√2 = 26.6 V
Answer is C
the rms current through a 4.7 kΩ resistor is 4 mA, the peak voltage drop across the resistor is
A. 4 V
B. 18.8 V
C. 26.6 V
D. 2.66 V
The answer is wrong
Right answer is 18.8 yaar