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Alternating Current and Voltage
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If the rms current through a 4.7 kΩ resistor is 4 mA, the peak voltage drop across the resistor is

Answer & Solution
Correct Answer: Option C
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2 Comments
Jacinta Boro
Jacinta Boro 2 years ago
V{RMS} = I{RMS} × R
V_{RMS} = 0.004× 4700= 18.8V
V_{peak} = V_{RMS} × √2
V_{peak = 18.8×√2 = 26.6 V
Answer is C
Leelamaya Mahakur
Leelamaya Mahakur 7 years ago
the rms current through a 4.7 kΩ resistor is 4 mA, the peak voltage drop across the resistor is
A. 4 V

B. 18.8 V

C. 26.6 V

D. 2.66 V
The answer is wrong
Right answer is 18.8 yaar