If the rotating mass of a rim type flywheel is distributed on another rim type flywheel whose mean radius is half the mean radius of the former, then energy stored in the latter at the same speed will be
A. Four times the first one
B. Same as the first one
C. One fourth of the first one
D. One and a half times the first one
Answer: Option C
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In considering friction of a V-thread, the virtual coefficient of friction (μ1) is given by
A. μ1 = μsinβ
B. μ1 = μcosβ
C. $${\mu _1} = \frac{\mu }{{\sin \beta }}$$
D. $${\mu _1} = \frac{\mu }{{\cos \beta }}$$
The lower pairs are _________ pairs.
A. Self-closed
B. Force-closed
C. Friction closed
D. None of these
In a coupling rod of a locomotive, each of the four pairs is a ________ pair.
A. Sliding
B. Turning
C. Rolling
D. Screw
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handu said: (Nov 12, 2013)
First flywheel mean radius = x.
Second flywheel mean radius = x/2 (condition given).
Energy storage (ES) = (1/2)I*omega^2.
ω1 = ω2 (condition given).
Energy storage first flywheel mean (ES) = I = mr^2 = mx^2.
Energy storage second flywheel mean (ES) = I = mr^2 = mx^2/4.
So 1/4th of the first one.