If the six digit number 15x1y2 is divisible by 44, then (x + y) is equal to:

Solution (By Examveda Team)

Divisibility law of 4: A number divisible by 4 if its last 2 digit is divisible by 4
Divisibility law of 11: If the difference of the alternating sum of digits of the number is a multiple of 11 (e.g. 2343 is divisible by 11 because 2 - 3 + 4 - 3 = 0, which is a multiple of 11).
⇒ 15x1y2 is divisible by 4 if y = 1 or 3
If y = 1, then
⇒ 15x112 is divisible by 11 if x = 6
If y = 3 then
⇒ 15x132 is divisible by 11 if x = 4
If y = 1 and x = 6, then
⇒ x + y = 1 + 6 = 7
If y = 3 and x = 4, then
⇒ x + y = 3 + 4 = 7