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If the square of sum of three positive consecutive natural number exceeds the sum of their squares by 292, then what is the largest of the three number?
Answer & Solution
Correct Answer:
Option
D
Go through option
[(x + 2) + (x + 1) + x]2 = [(x + 2)2 + (x + 1)2 + x2] + 292
Let x = 3
(5 + 4 + 3)2 = 25 + 16 + 9 + 292
144 < 342
Option D, x = 6
(8 + 7 + 6)2 = 64 + 49 + 36 + 292
441 = 441
∴ Option D satisfy this equation
So, largest is 8.
[(x + 2) + (x + 1) + x]2 = [(x + 2)2 + (x + 1)2 + x2] + 292
Let x = 3
(5 + 4 + 3)2 = 25 + 16 + 9 + 292
144 < 342
Option D, x = 6
(8 + 7 + 6)2 = 64 + 49 + 36 + 292
441 = 441
∴ Option D satisfy this equation
So, largest is 8.
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