If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
A. $$\frac{3}{{52}}$$
B. $$\frac{1}{{52}}$$
C. $$\frac{5}{{52}}$$
D. $$\frac{7}{{52}}$$
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{Lets first number}} = a \cr & {\text{Second number}} = b \cr & a + b = 65 \cr & \sqrt {a \times b} = 26 \cr & ab = 676 \cr & {\text{Sum of reciprocal}} = \frac{1}{a} + \frac{1}{b} \cr & = \frac{{b + a}}{{ab}} \cr & = \frac{{65}}{{676}} \cr & = \frac{5}{{52}} \cr} $$Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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