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If there is 6 A of current through the filament of a lamp, how many coulombs of charge move through the filament in 1.75 s?
Answer & Solution
Correct Answer:
Option
A
The question asks us to find the amount of charge (in coulombs) that flows through a lamp filament given the current and time.
Remember the fundamental relationship between current (I), charge (Q), and time (t): I = Q/t
Where:
I is the current in Amperes (A)
Q is the charge in Coulombs (C)
t is the time in seconds (s)
We are given:
Current, I = 6 A
Time, t = 1.75 s
We need to find Q.
Rearranging the formula to solve for Q, we get: Q = I * t
Substitute the given values:
Q = 6 A * 1.75 s
Q = 10.5 C
Therefore, the correct answer is Option A: 10.5 C.
Remember the fundamental relationship between current (I), charge (Q), and time (t): I = Q/t
Where:
I is the current in Amperes (A)
Q is the charge in Coulombs (C)
t is the time in seconds (s)
We are given:
Current, I = 6 A
Time, t = 1.75 s
We need to find Q.
Rearranging the formula to solve for Q, we get: Q = I * t
Substitute the given values:
Q = 6 A * 1.75 s
Q = 10.5 C
Therefore, the correct answer is Option A: 10.5 C.
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LoginQ = I*time,
Q = 6*1.75= 10.5 As
= 10.5 C