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# If two numbers are respectively 30% and 40% more than a third number, what percent is the first of the second?

A. $$92\frac{6}{7}\%$$

B. $$84\frac{4}{5}\%$$

C. 80%

D. 75%

### Solution(By Examveda Team)

Let the third number be 100. Then,
1st number = 130
2nd number = 140
% 1st number to the 2nd number
\eqalign{ & = \frac{{130 \times 100}}{{140}} \cr & = \frac{{650}}{7} \cr & = 92\frac{6}{7}\% \cr}