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If two numbers are respectively 30% and 40% more than a third number, what percent is the first of the second?
Answer & Solution
Correct Answer:
Option
A
Let the third number be 100. Then,
1st number = 130
2nd number = 140
% 1st number to the 2nd number
$$\eqalign{ & = \frac{{130 \times 100}}{{140}} \cr & = \frac{{650}}{7} \cr & = 92\frac{6}{7}\% \cr} $$
1st number = 130
2nd number = 140
% 1st number to the 2nd number
$$\eqalign{ & = \frac{{130 \times 100}}{{140}} \cr & = \frac{{650}}{7} \cr & = 92\frac{6}{7}\% \cr} $$
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Login=(13/14)*100 ____
=(13/7)*50. 7 | 650
=650/7. 63
=92(6/7)%. ----------
20
14
---------
6
Take quotient (92) +remainder(6)/divisor(7)=92 (6/7)%
20
14
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6
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The first number is 30% more than x, which means it is equal to x + 0.3x = 1.3x.
The second number is 40% more than x, which means it is equal to x + 0.4x = 1.4x.
We need to find the percentage of the first number (1.3x) in relation to the second number (1.4x).
To do this, we can divide the first number by the second number and then multiply by 100 to get the percentage:
(1.3x / 1.4x) * 100 = (13/14) * 100 = 92.857...
Rounding this to the nearest whole number, we get approximately 93%.
Approximately A is the answer
Plz explain