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If two numbers are respectively 30% and 40% more than a third number, what percent is the first of the second?

A. $$92\frac{6}{7}\% $$

B. $$84\frac{4}{5}\% $$

C. 80%

D. 75%

Answer: Option A

Solution(By Examveda Team)

Let the third number be 100. Then,
1st number = 130
2nd number = 140
% 1st number to the 2nd number
$$\eqalign{ & = \frac{{130 \times 100}}{{140}} \cr & = \frac{{650}}{7} \cr & = 92\frac{6}{7}\% \cr} $$

This Question Belongs to Arithmetic Ability >> Percentage

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Comments ( 4 )

  1. Abduselam Isak
    Abduselam Isak :
    4 months ago

    To solve this problem, let's assume the third number is x.

    The first number is 30% more than x, which means it is equal to x + 0.3x = 1.3x.

    The second number is 40% more than x, which means it is equal to x + 0.4x = 1.4x.

    We need to find the percentage of the first number (1.3x) in relation to the second number (1.4x).

    To do this, we can divide the first number by the second number and then multiply by 100 to get the percentage:

    (1.3x / 1.4x) * 100 = (13/14) * 100 = 92.857...

    Rounding this to the nearest whole number, we get approximately 93%.

    Approximately A is the answer

  2. Nani Reddy
    Nani Reddy :
    5 years ago

    Such a bull shit

  3. Sangeeta Rani
    Sangeeta Rani :
    6 years ago

    how 130/140*100 is divided

  4. Suneel Kumar
    Suneel Kumar :
    7 years ago

    How (130/140)*100 has become 92(6/7)%

    Plz explain

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