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If 'x' is the depth of flow in an open channel of large width, then the hydraulic radius is equal to

A. x

B. $$\frac{{\text{x}}}{2}$$

C. $$\frac{{\text{x}}}{3}$$

D. $$\frac{{2{\text{x}}}}{3}$$

Answer: Option A


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Comments ( 2 )

  1. Zohaib Nadeem
    Zohaib Nadeem :
    4 years ago

    Rh = (x*W)/((2*x)+W)
    Since W>>x neglect x in denominator
    Rh = (x*W)/W
    Rh = x

  2. Muhammad Moazzam
    Muhammad Moazzam :
    4 years ago

    Rh=flow area / wetted perimeter = (W * X) / (2 * (X+W)).
    Since W (width)>>>X , Rh= (W * X)/(2 * W)= X/2.
    So, I think the answer is B.

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