If x, y, z and w be the digits of a number beginning from the left, the number is :
A. xyzw
B. wzyx
C. x + 10y + 100z + 1000w
D. 103x + 102y + 10z + w
Answer: Option D
Solution (By Examveda Team)
Let the thousand's, hundred's, ten's, and one's digits be x, y, z, w respectively.Then, the number is
1000x + 100y + 10z + w
= 103x + 102y + 10z + w
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