If xsin60°.tan30° - tan245° = cosec60°.cot30° - sec245° then x = ?
A. 2
B. -2
C. 6
D. -4
Answer: Option A
Solution(By Examveda Team)
$${\text{ }}x\sin {60^ \circ }.\tan {30^ \circ } - \tan^2 {45^ \circ } = $$ $$\operatorname{cosec} {60^ \circ }.$$ $$\cot {30^ \circ } - $$ $${\sec ^2}{45^ \circ }$$$$\eqalign{ & \Rightarrow x \times \frac{{\sqrt 3 }}{2} \times \frac{1}{{\sqrt 3 }} - 1 = \frac{2}{{\sqrt 3 }} \times \sqrt 3 - {\left( {\sqrt 2 } \right)^2} \cr & \Rightarrow \frac{x}{2} - 1 = 2 - 2 \cr & \Rightarrow \frac{x}{2} - 1 = 0 \cr & \Rightarrow \frac{x}{2} = 1 \cr & \Rightarrow x = 2 \cr} $$
Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
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