If, $$Y = {k_1}\left[ {1 - \exp \left( {\frac{{{k_2}\Delta x}}{{{k_3}x}}} \right)} \right],$$ where k1, k2 and k3 are constants. If k2ΔX < ΔX, the value of γ up to first order of approximation would be
A. $$Y = {k_1}\left[ {1 - \frac{{{k_2}\Delta x}}{{{k_3}x}}} \right]$$
B. $$Y = {k_1}\left[ {1 + \frac{{{k_2}\Delta x}}{{{k_3}x}}} \right]$$
C. $$Y = {k_1}1 - \frac{{{k_2}\Delta x}}{{{k_3}x}}$$
D. $$Y = - {k_1}1\frac{{{k_2}\Delta x}}{{{k_3}x}}$$
Answer: Option C
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