# If you wish to increase the amount of current in a resistor from 120 mA to 160 mA by changing the 24 V source, what should the new voltage setting be?

A. 8 V

B. 320 V

C. 3.2 V

D. 32 V

**Answer: Option D **

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Related Questions on Ohms Law

**A current of 200 µA through a 6.8 kΩ resistor produces a voltage drop of
**

A. 34.4 V

B. 340 V

C. 13.6 V

D. 1.36 V

A. V is directly proportional to I

B. V is inversely proportional to I

C. V is directly proportional to vI

D. All of the above

**How much resistance is needed to draw 17.6 mA from a 12 volt source?**

A. 212 Ω

B. 6.8 kΩ

C. 68 Ω

D. 680 Ω

Fists we calculate the resistance of 120mA and 24v.

So the value of resistance is= 24/(120*(10-3))

= 200 ohms

Now we calculate the new voltage at 200ohms and current value of 160mA

So the final answer is 32V