Examveda

If z = xy $$l$$n(xy), then

A. $${\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} + {\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}} = 0$$

B. $${\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} = {\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}}$$

C. $${\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} = {\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}}$$

D. $${\text{y}}\frac{{\partial {\text{z}}}}{{\partial {\text{x}}}} + {\text{x}}\frac{{\partial {\text{z}}}}{{\partial {\text{y}}}} = 0$$

Answer: Option C


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