If $$\theta $$ be acute angle and $$\cos \theta = \frac{{15}}{{17}}{\text{,}}$$   then the value of $${\text{cot}}\left( {{{90}^ \circ } - \theta } \right)$$   is?

$$\cos \theta = \frac{{15 \to {\text{Base}}}}{{17 \to {\text{Hypo}}}}$$

$$\eqalign{ & {\text{Perpendicular = 8}} \cr & \Rightarrow {\text{cot}}\left( {{{90}^ \circ } - \theta } \right) \cr & \Rightarrow {\text{tan}}\theta = \frac{8}{{15}}\left[ {\therefore \tan \theta = \frac{{\text{P}}}{{\text{B}}}} \right] \cr} $$