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If $$\alpha $$ = 0.98, $${I_{{\text{CO}}}} = 6\mu {\text{A}}$$   and $${I_\beta } = 100\mu {\text{A}}$$   for a transistor, then the value of $${I_{\text{C}}}$$ will be

Answer & Solution
Correct Answer: Option D
$$\eqalign{ & {I_{\text{C}}} = \frac{{{I_{{\text{CO}}}}}}{{1 - \alpha }} + \frac{\alpha }{{1 - \alpha }} \times {I_\beta } \cr & = \frac{6}{{1 - 0.98}} + \frac{{0.98}}{{1 - 0.98}} \times 100 \cr & = 5.2\,{\text{mA}} \cr} $$
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3 Comments
Khuram Shahzad
Khuram Shahzad 6 years ago
β = α/(1-α) ; Ic = βIc + (1 + β)Ico = 5.2 mA
Asad Hameed
Asad Hameed 6 years ago
there is a mistake in the formula current formula is Ic = β* Ib + (1 + β)Ico
Amit Kumar
Amit Kumar 8 years ago
FORMULA???