Ifa number K = 42 × 25 × 54 × 135 is divisible by 3^a, then find the maximum value of a

A. 6

B. 7

C. 4

D. 5

Answer: Option B

Solution(By Examveda Team)

K = 42 × 25 × 54 × 135
K = 3 × 14 × 25 × 3³ × 2 × 3³ × 5
= 3⁷ × 14 × 25 × 2 × 5
= It is divided by 3⁷, which is equal to 3^a   (given)
⇒ So, 3⁷ = 3^a
a = 7