In a beam the local bond stress Sb, is equal to
A. $$\frac{{{\text{Shear force}}}}{{{\text{Leaver arm}} \times {\text{Total perimeter of reinforcement}}}}$$
B. $$\frac{{{\text{Total perimeter of reinforcement}}}}{{{\text{Leaver arm}} \times {\text{Shear force}}}}$$
C. $$\frac{{{\text{Leaver arm}}}}{{{\text{Shear force}} \times {\text{Total perimeter of reinforcement}}}}$$
D. $$\frac{{{\text{Leaver arm}}}}{{{\text{Bending moment}} \times {\text{Total perimeter of reinforcement}}}}$$
Answer: Option A
This Question Belongs to Civil Engineering >> RCC Structures Design
Distribution of shear intensity over a rectangular section of a beam, follows:
A. A circular curve
B. A straight line
C. A parabolic curve
D. An elliptical curve
If the shear stress in a R.C.C. beam is
A. Equal or less than 5 kg/cm2, no shear reinforcement is provided
B. Greater than 4 kg/cm2, but less than 20 kg/cm2, shear reinforcement is provided
C. Greater than 20 kg/cm2, the size of the section is changed
D. All the above
In a pre-stressed member it is advisable to use
A. Low strength concrete only
B. High strength concrete only
C. Low strength concrete but high tensile steel
D. High strength concrete and high tensile steel
In a simply supported slab, alternate bars are curtailed at
A. $${\frac{1}{4}^{{\text{th}}}}$$ of the span
B. $${\frac{1}{5}^{{\text{th}}}}$$ of the span
C. $${\frac{1}{6}^{{\text{th}}}}$$ of the span
D. $${\frac{1}{7}^{{\text{th}}}}$$ of the span
Join The Discussion