In a charity show tickets numbered consecutively from 101 through 350 are placed in a box.
What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?

A. 0.285

B. 0.40

C. $$\frac{{100}}{{249}}$$

D. $$\frac{{99}}{{250}}$$

Answer: Option B

Solution(By Examveda Team)

250 numbers between 101 and 350 i.e. n(S) = 250
n(E) = 100^th digits of 2 = 299 - 199 = 100
$$\eqalign{ & P(E) = \frac{{n(E)}}{{n(S)}} \cr & = \frac{{100}}{{250}} \cr & = 0.40 \cr} $$