In a charity show tickets numbered consecutively from 101 through 350 are placed in a box.
What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?
A. 0.285
B. 0.40
C. $$\frac{{100}}{{249}}$$
D. $$\frac{{99}}{{250}}$$
Answer: Option B
Solution (By Examveda Team)
250 numbers between 101 and 350 i.e. n(S) = 250n(E) = 100th digits of 2 = 299 - 199 = 100
$$\eqalign{ & P(E) = \frac{{n(E)}}{{n(S)}} \cr & = \frac{{100}}{{250}} \cr & = 0.40 \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
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