In a class the number of girls is 20% more than that of the boys. The strength of the class is 66. If 4 more girls are admitted to the class, the ratio of the number of boys to that of the girls is -
A. 1 : 2
B. 1 : 4
C. 3 : 4
D. 3 : 5
Answer: Option C
Solution(By Examveda Team)
Let the number of boys be x$$\eqalign{ & {\text{Then,}} \cr & {\text{Number of girls}} \cr & = 120\% {\text{ of }}x = \frac{{6x}}{5} \cr & \therefore x + \frac{{6x}}{5} = 66 \cr & \Rightarrow \frac{{11x}}{5} = 66 \cr & \Rightarrow x = \frac{{66 \times 5}}{{11}} \cr & = 30 \cr & {\text{So, number of boys}} \cr & = 30 \cr & {\text{And, new number of girls}} \cr & = \left( {\frac{{6 \times 30}}{5}} \right) + 4 = 40 \cr & \therefore {\text{Required ratio}} \cr & = 30:40 \cr & = 3:4 \cr} $$
Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
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