In a division sum, the remainder was 71. With the same divisor but twice the dividend, the remainder is 43. Which one of the following is the divisor ?
A. 86
B. 93
C. 99
D. 104
Answer: Option C
Solution(By Examveda Team)
Let the dividend be (x + 71) and the divisor be y.Then, [2(x + 71) - 43] is divisible by y
⇒ (2x + 142 - 43) is divisible by y
⇒ (2x + 99) is divisible by y
∴ Divisor = 99
Shortcut method
Divisor = (2 × 71 - 43) = (142 - 43) = 99
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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