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This question belongs to Arithmetic Ability Number System
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In a division sum, the remainder was 71. With the same divisor but twice the dividend, the remainder is 43. Which one of the following is the divisor ?

Answer & Solution
Correct Answer: Option C
Let the dividend be (x + 71) and the divisor be y.
Then, [2(x + 71) - 43] is divisible by y
⇒ (2x + 142 - 43) is divisible by y
⇒ (2x + 99) is divisible by y
∴ Divisor = 99

Shortcut method
Divisor = (2 × 71 - 43) = (142 - 43) = 99
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