In a drawer there are 4 white socks, 3 blue socks and 5 grey socks. Two socks are picked randomly. What is the possibility that both the socks are of same color?
A. $$\frac{{4}}{{11}}$$
B. 1
C. $$\frac{{2}}{{33}}$$
D. $$\frac{{19}}{{66}}$$
Answer: Option D
Solution(By Examveda Team)
Total socks = 4 + 3 + 5 = 12We want same color socks
So we want, 2 white or 2 blue or 2 grey socks
For white :
Probability of 1st sock being white = $$\frac{{4}}{{12}}$$
Probability of 2nd sock being white = $$\frac{{3}}{{11}}$$
White Probability
$$\eqalign{ & = \frac{4}{{12}} \times \frac{3}{{11}} \cr & = \frac{1}{{11}} \cr} $$
Similarly,
Blue Probability
$$\eqalign{ & = \frac{3}{{12}} \times \frac{2}{{11}} \cr & = \frac{1}{{22}} \cr} $$
Grey Probability
$$\eqalign{ & = \frac{5}{{12}} \times \frac{4}{{11}} \cr & = \frac{5}{{33}} \cr} $$
∴ Total Probability
$$\eqalign{ & = \frac{1}{{11}} + \frac{1}{{22}} + \frac{5}{{33}} \cr & = \frac{{19}}{{66}} \cr} $$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
Join The Discussion