In a four-bar chain it is required to give an oscillatory motion to the follower for a continuous rotation of the crank. For the lengths of 50 mm of crank and 70 mm of the follower, determine theoretical maximum length of coupler. The distance between fixed pivots of crank and followers is

Thanush Durairajan 6 years ago

Crank Diameter = 50
Convert into Radius = 50/2 = 25
So, 25 + (Length of follower) 70= 95mm
If we Pivoted at 95mm there won't be Proper Oscillation.
Ans: " Slightly lesser than 95mm "

Thanush Durairajan 6 years ago

Crank Diameter = 50
Convert into Radius = 50/2 = 25
So, 25 + (Length of follower) 70= 95mm
If we Pivoted at 95mm there won't be Proper Oscillation.
Ans: " Slightly lesser than 95mm "

Sachidanand Pandey 6 years ago

Solves in question please suppose that four bar chain required to given an excellent motion is the the follower of the continuous rotation of the Crank the length of 50mm Crank and 70mm how less than 95slightly

Sai Prathap 6 years ago

L+S

Nkit Rajpoot 7 years ago

25+70= 95 ...length should be less than because for oscillating condition

Praveen Kakara 7 years ago

Explain please

Praveen Kakara 7 years ago

Explain please

Tarun Kumar 7 years ago

Crank(P) =50
Follower/rocker(Q) =70
S+L

Nitin Bagade 7 years ago

please explain

Patel Sandip 7 years ago

Plz explain it

Manohar Kumar 7 years ago

Please explain it

Adithya Sb 7 years ago

Plz plz explain this for me plz