Examveda

In a lock-gate, the reaction between two gates is (where P = Resultant pressure on the lock gate and $$\alpha $$ = Inclination of the gate with the normal to the side of the lock)

A. $$\frac{{\text{P}}}{{\sin \alpha }}$$

B. $$\frac{{2{\text{P}}}}{{\sin \alpha }}$$

C. $$\frac{{\text{P}}}{{2\sin \alpha }}$$

D. $$\frac{{2{\text{P}}}}{{\sin \frac{\alpha }{2}}}$$

Answer: Option C


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Comments (1)

  1. Madhavan Palmani
    Madhavan Palmani:
    6 years ago

    Assume lock gate is a simply supported beam so load is eually devided at both the supports ie p/2 sina.

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