In a p+n junction diode under reverse bias, the magnitude of electric field is maximum at
A. The edge of the depletion region on the p-side
B. The edge of the depletion region on the n-side
C. The p+n junction
D. The center of the depletion region on the n-side
Answer: Option C
Solution (By Examveda Team)
Option A: The edge of the depletion region on the p-sideAt the edge of the depletion region on the p-side, the electric field is not maximum. The field strength gradually reduces as you move away from the junction towards the edges of the depletion region. Therefore, this option is incorrect.
Option B: The edge of the depletion region on the n-side
Similarly, at the edge of the depletion region on the n-side, the electric field is not at its peak. The field strength diminishes as you approach the edges of the depletion region. Thus, this option is incorrect.
Option C: The p+n junction
In a p+n junction diode under reverse bias, the electric field is maximum at the junction itself. This is because the maximum charge separation occurs at the junction, resulting in the highest electric field strength. Hence, this option is correct.
Option D: The center of the depletion region on the n-side
The center of the depletion region on the n-side does not experience the maximum electric field. As you move away from the junction, the electric field strength decreases, making this option incorrect.
Conclusion:
In a p+n junction diode under reverse bias, the magnitude of the electric field is maximum at the p+n junction (Option C).
Why pn