In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
A. $$\frac{{5}}{{21}}$$
B. $$\frac{{5}}{{14}}$$
C. $$\frac{{9}}{{14}}$$
D. $$\frac{{16}}{{21}}$$
Answer: Option A
Solution(By Examveda Team)
Number of ways of (selecting at least two couples among five people selected) = $$\left( {{}^5{C_2} \times {}^6{C_1}} \right)$$As remaining person can be any one among three couples left.
Required probability
$$\eqalign{ & = \frac{{{}^5{C_2} \times {}^6{C_1}}}{{{}^{10}{C_5}}} \cr & = \frac{{\left( {10 \times 6} \right)}}{{252}} \cr & = \frac{5}{{21}} \cr} $$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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